Let D be a mapping from an alternative ring into itself satisfying D(a⋅ba)= D(a)⋅ba+a⋅D(b)a+a⋅bD(a) for all a, b. Under some conditions on , we show that D is additive.
Descargo de responsabilidad: este resumen se tradujo utilizando herramientas de inteligencia artificial y aún no ha sido revisado ni verificado
into itself satisfying D(a⋅ba)= D(a)⋅ba+a⋅D(b)a+a⋅bD(a) for all a, b 
English 
Chinese 
Russian 
German 
French 
Japanese 
Portuguese 
Hindi 